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7a^2+32a-15=0
a = 7; b = 32; c = -15;
Δ = b2-4ac
Δ = 322-4·7·(-15)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-38}{2*7}=\frac{-70}{14} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+38}{2*7}=\frac{6}{14} =3/7 $
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